Line slope calculator 3x+4y=32


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[0; 8] and B[4; 5]

Calculation:

Slope: m = -0.75

Slope-intercept form of line: y = -0.75x+8

Canonical form of the line equation: 3x+4y-32 = 0

Parametric form of the line equation:
x = 4t
y = -3t+8      ; t ∈ R

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 10.6667

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 6.4

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [2; 6.5]

Perpendicular Bisector equation: 4x-3y+11.5 = 0

Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (4; 5) ;   |OB| = 6.4031
Scalar product OA .OB = 40
Angle ∠ AOB = 38°39'35″ = 0.6747 rad