Line slope calculator 2x+4y=32
Straight line given by points A[0; 8] and B[4; 6]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+8
Canonical form of the line equation: 2x+4y-32 = 0
Parametric form of the line equation:
x = 4t
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 16
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 7.1554
The length of the segment AB: |AB| = 4.4721
Vector: AB = (4; -2)
Normal vector: n = (2; 4)
Midpoint of the segment AB: M = [2; 7]
Perpendicular Bisector equation: 4x-2y+6 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (4; 6) ; |OB| = 7.2111
Scalar product OA .OB = 48
Angle ∠ AOB = 33°41'24″ = 0.588 rad