Line slope calculator 2x+4y=32


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[4; 6]

Calculation:

Slope-intercept form of line: y = -0.5x+8

Canonical form of the line equation: 2x+4y-32 = 0

Parametric form of the line equation:
x = 4t
y = -2t+8      ; t ∈ R

Slope: m = -0.5

Slope angle of line: φ = -26°33'54″ = -0.4636 rad

X intercept: x0 = 16

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 7.1554

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; -2)

Normal vector: n = (2; 4)

Midpoint of the segment AB: M = [2; 7]

Perpendicular Bisector equation: 4x-2y+6 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (4; 6) ;   |OB| = 7.2111
Scalar product OA .OB = 48
Angle ∠ AOB = 33°41'24″ = 0.588 rad