Line slope calculator 8x+5y=40


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -1.6x+8

Canonical form of the line equation: 8x+5y-40 = 0

Parametric form of the line equation:
x = 5t
y = -8t+8      ; t ∈ R

Slope: m = -1.6

Slope angle of line: φ = -57°59'41″ = -1.0122 rad

X intercept: x0 = 5

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 4.24

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; -8)

Normal vector: n = (8; 5)

Midpoint of the segment AB: M = [2.5; 4]

Perpendicular Bisector equation: 5x-8y+19.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 0
Angle ∠ AOB = 90° = 1.5708 rad