Line slope calculator 7x+5y=40
Straight line given by points A[0; 8] and B[5; 1]
Calculation:
Slope: m = -1.4Slope-intercept form of line: y = -1.4x+8
Canonical form of the line equation: 7x+5y-40 = 0
Parametric form of the line equation:
x = 5t
y = -7t+8 ; t ∈ R
Slope angle of line: φ = -54°27'44″ = -0.9505 rad
X intercept: x0 = 5.7143
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 4.6499
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; -7)
Normal vector: n = (7; 5)
Midpoint of the segment AB: M = [2.5; 4.5]
Perpendicular Bisector equation: 5x-7y+19 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 8
Angle ∠ AOB = 78°41'24″ = 1.3734 rad