Line slope calculator 7x+5y=40


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[5; 1]

Calculation:

Slope-intercept form of line: y = -1.4x+8

Canonical form of the line equation: 7x+5y-40 = 0

Parametric form of the line equation:
x = 5t
y = -7t+8      ; t ∈ R

Slope: m = -1.4

Slope angle of line: φ = -54°27'44″ = -0.9505 rad

X intercept: x0 = 5.7143

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 4.6499

The length of the segment AB: |AB| = 8.6023

Vector: AB = (5; -7)

Normal vector: n = (7; 5)

Midpoint of the segment AB: M = [2.5; 4.5]

Perpendicular Bisector equation: 5x-7y+19 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (5; 1) ;   |OB| = 5.099
Scalar product OA .OB = 8
Angle ∠ AOB = 78°41'24″ = 1.3734 rad