Line slope calculator 6x+5y=40
Straight line given by points A[0; 8] and B[5; 2]
Calculation:
Slope: m = -1.2Slope-intercept form of line: y = -1.2x+8
Canonical form of the line equation: 6x+5y-40 = 0
Parametric form of the line equation:
x = 5t
y = -6t+8 ; t ∈ R
Slope angle of line: φ = -50°11'40″ = -0.8761 rad
X intercept: x0 = 6.6667
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 5.1215
The length of the segment AB: |AB| = 7.8102
Vector: AB = (5; -6)
Normal vector: n = (6; 5)
Midpoint of the segment AB: M = [2.5; 5]
Perpendicular Bisector equation: 5x-6y+17.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 16
Angle ∠ AOB = 68°11'55″ = 1.1903 rad