Line slope calculator 6x+5y=40


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -1.2x+8

Canonical form of the line equation: 6x+5y-40 = 0

Parametric form of the line equation:
x = 5t
y = -6t+8      ; t ∈ R

Slope: m = -1.2

Slope angle of line: φ = -50°11'40″ = -0.8761 rad

X intercept: x0 = 6.6667

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 5.1215

The length of the segment AB: |AB| = 7.8102

Vector: AB = (5; -6)

Normal vector: n = (6; 5)

Midpoint of the segment AB: M = [2.5; 5]

Perpendicular Bisector equation: 5x-6y+17.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 16
Angle ∠ AOB = 68°11'55″ = 1.1903 rad