Line slope calculator 4x+5y=40
Straight line given by points A[0; 8] and B[5; 4]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+8
Canonical form of the line equation: 4x+5y-40 = 0
Parametric form of the line equation:
x = 5t
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 10
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 6.247
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [2.5; 6]
Perpendicular Bisector equation: 5x-4y+11.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (5; 4) ; |OB| = 6.4031
Scalar product OA .OB = 32
Angle ∠ AOB = 51°20'25″ = 0.8961 rad