Line slope calculator 4x+5y=40


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[5; 4]

Calculation:

Slope-intercept form of line: y = -0.8x+8

Canonical form of the line equation: 4x+5y-40 = 0

Parametric form of the line equation:
x = 5t
y = -4t+8      ; t ∈ R

Slope: m = -0.8

Slope angle of line: φ = -38°39'35″ = -0.6747 rad

X intercept: x0 = 10

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 6.247

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; -4)

Normal vector: n = (4; 5)

Midpoint of the segment AB: M = [2.5; 6]

Perpendicular Bisector equation: 5x-4y+11.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (5; 4) ;   |OB| = 6.4031
Scalar product OA .OB = 32
Angle ∠ AOB = 51°20'25″ = 0.8961 rad