Line slope calculator 3x+5y=40


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[5; 5]

Calculation:

Slope-intercept form of line: y = -0.6x+8

Canonical form of the line equation: 3x+5y-40 = 0

Parametric form of the line equation:
x = 5t
y = -3t+8      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 13.3333

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 6.8599

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [2.5; 6.5]

Perpendicular Bisector equation: 5x-3y+7 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 40
Angle ∠ AOB = 45° = 0.7854 rad