Line slope calculator 3x+5y=40
Straight line given by points A[0; 8] and B[5; 5]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+8
Canonical form of the line equation: 3x+5y-40 = 0
Parametric form of the line equation:
x = 5t
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 13.3333
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 6.8599
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [2.5; 6.5]
Perpendicular Bisector equation: 5x-3y+7 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 40
Angle ∠ AOB = 45° = 0.7854 rad