Line slope calculator 2x+5y=40
Straight line given by points A[0; 8] and B[5; 6]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+8
Canonical form of the line equation: 2x+5y-40 = 0
Parametric form of the line equation:
x = 5t
y = -2t+8 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 20
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 7.4278
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [2.5; 7]
Perpendicular Bisector equation: 5x-2y+1.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 48
Angle ∠ AOB = 39°48'20″ = 0.6947 rad