Line slope calculator 2x+5y=40


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[5; 6]

Calculation:

Slope-intercept form of line: y = -0.4x+8

Canonical form of the line equation: 2x+5y-40 = 0

Parametric form of the line equation:
x = 5t
y = -2t+8      ; t ∈ R

Slope: m = -0.4

Slope angle of line: φ = -21°48'5″ = -0.3805 rad

X intercept: x0 = 20

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 7.4278

The length of the segment AB: |AB| = 5.3852

Vector: AB = (5; -2)

Normal vector: n = (2; 5)

Midpoint of the segment AB: M = [2.5; 7]

Perpendicular Bisector equation: 5x-2y+1.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (5; 6) ;   |OB| = 7.8102
Scalar product OA .OB = 48
Angle ∠ AOB = 39°48'20″ = 0.6947 rad