Line slope calculator 7x+8y=64


Enter coordinates of two different points:

Straight line given by points A[0; 8] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.875x+8

Canonical form of the line equation: 7x+8y-64 = 0

Parametric form of the line equation:
x = 8t
y = -7t+8      ; t ∈ R

Slope: m = -0.875

Slope angle of line: φ = -41°11'9″ = -0.7188 rad

X intercept: x0 = 9.1429

Y intercept: y0 = q = 8

Distance line from the origin: d0 = 6.0206

The length of the segment AB: |AB| = 10.6301

Vector: AB = (8; -7)

Normal vector: n = (7; 8)

Midpoint of the segment AB: M = [4; 4.5]

Perpendicular Bisector equation: 8x-7y-0.5 = 0


Vector OA = (0; 8) ;   |OA| = 8
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 8
Angle ∠ AOB = 82°52'30″ = 1.4464 rad