Line slope calculator 3x+8y=64
Straight line given by points A[0; 8] and B[8; 5]
Calculation:
Slope: m = -0.375Slope-intercept form of line: y = -0.375x+8
Canonical form of the line equation: 3x+8y-64 = 0
Parametric form of the line equation:
x = 8t
y = -3t+8 ; t ∈ R
Slope angle of line: φ = -20°33'22″ = -0.3588 rad
X intercept: x0 = 21.3333
Y intercept: y0 = q = 8
Distance line from the origin: d0 = 7.4906
The length of the segment AB: |AB| = 8.544
Vector: AB = (8; -3)
Normal vector: n = (3; 8)
Midpoint of the segment AB: M = [4; 6.5]
Perpendicular Bisector equation: 8x-3y-12.5 = 0
Vector OA = (0; 8) ; |OA| = 8
Vector OB = (8; 5) ; |OB| = 9.434
Scalar product OA .OB = 40
Angle ∠ AOB = 57°59'41″ = 1.0122 rad