Line slope calculator 5x-3y=5
Straight line given by points A[1; 0] and B[4; 5]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x-1.6667
Canonical form of the line equation: 5x-3y-5 = 0
Parametric form of the line equation:
x = 3t+1
y = 5t ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = 1
Y intercept: y0 = q = -1.6667
Distance line from the origin: d0 = 0.8575
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [2.5; 2.5]
Perpendicular Bisector equation: 3x+5y-20 = 0
Vector OA = (1; 0) ; |OA| = 1
Vector OB = (4; 5) ; |OB| = 6.4031
Scalar product OA .OB = 4
Angle ∠ AOB = 51°20'25″ = 0.8961 rad