Line slope calculator x-4y=1
Straight line given by points A[1; 0] and B[5; 1]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x-0.25
Canonical form of the line equation: x-4y-1 = 0
Parametric form of the line equation:
x = 4t+1
y = t ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = 1
Y intercept: y0 = q = -0.25
Distance line from the origin: d0 = 0.2425
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [3; 0.5]
Perpendicular Bisector equation: 4x+y-12.5 = 0
Vector OA = (1; 0) ; |OA| = 1
Vector OB = (5; 1) ; |OB| = 5.099
Scalar product OA .OB = 5
Angle ∠ AOB = 11°18'36″ = 0.1974 rad