Line slope calculator 5x-4y=5
Straight line given by points A[1; 0] and B[5; 5]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-1.25
Canonical form of the line equation: 5x-4y-5 = 0
Parametric form of the line equation:
x = 4t+1
y = 5t ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 1
Y intercept: y0 = q = -1.25
Distance line from the origin: d0 = 0.7809
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [3; 2.5]
Perpendicular Bisector equation: 4x+5y-24.5 = 0
Vector OA = (1; 0) ; |OA| = 1
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 5
Angle ∠ AOB = 45° = 0.7854 rad