Line slope calculator 8x-5y=8


Enter coordinates of two different points:

Straight line given by points A[1; 0] and B[6; 8]

Calculation:

Slope-intercept form of line: y = 1.6x-1.6

Canonical form of the line equation: 8x-5y-8 = 0

Parametric form of the line equation:
x = 5t+1
y = 8t      ; t ∈ R

Slope: m = 1.6

Slope angle of line: φ = 57°59'41″ = 1.0122 rad

X intercept: x0 = 1

Y intercept: y0 = q = -1.6

Distance line from the origin: d0 = 0.848

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; 8)

Normal vector: n = (8; -5)

Midpoint of the segment AB: M = [3.5; 4]

Perpendicular Bisector equation: 5x+8y-49.5 = 0


Vector OA = (1; 0) ;   |OA| = 1
Vector OB = (6; 8) ;   |OB| = 10
Scalar product OA .OB = 6
Angle ∠ AOB = 53°7'48″ = 0.9273 rad