Line slope calculator x+9y=10


Enter coordinates of two different points:

Straight line given by points A[1; 1] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -0.1111x+1.1111

Canonical form of the line equation: x+9y-10 = 0

Parametric form of the line equation:
x = 9t+1
y = -t+1      ; t ∈ R

Slope: m = -0.1111

Slope angle of line: φ = -6°20'25″ = -0.1107 rad

X intercept: x0 = 10

Y intercept: y0 = q = 1.1111

Distance line from the origin: d0 = 1.1043

The length of the segment AB: |AB| = 9.0554

Vector: AB = (9; -1)

Normal vector: n = (1; 9)

Midpoint of the segment AB: M = [5.5; 0.5]

Perpendicular Bisector equation: 9x-y-49 = 0


Vector OA = (1; 1) ;   |OA| = 1.4142
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 10
Angle ∠ AOB = 45° = 0.7854 rad