Line slope calculator x+4y=5
Straight line given by points A[1; 1] and B[5; 0]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+1.25
Canonical form of the line equation: x+4y-5 = 0
Parametric form of the line equation:
x = 4t+1
y = -t+1 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 5
Y intercept: y0 = q = 1.25
Distance line from the origin: d0 = 1.2127
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [3; 0.5]
Perpendicular Bisector equation: 4x-y-11.5 = 0
Vector OA = (1; 1) ; |OA| = 1.4142
Vector OB = (5; 0) ; |OB| = 5
Scalar product OA .OB = 5
Angle ∠ AOB = 45° = 0.7854 rad