Line slope calculator x-4y=-3
Straight line given by points A[1; 1] and B[5; 2]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+0.75
Canonical form of the line equation: x-4y+3 = 0
Parametric form of the line equation:
x = 4t+1
y = t+1 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -3
Y intercept: y0 = q = 0.75
Distance line from the origin: d0 = 0.7276
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [3; 1.5]
Perpendicular Bisector equation: 4x+y-13.5 = 0
Vector OA = (1; 1) ; |OA| = 1.4142
Vector OB = (5; 2) ; |OB| = 5.3852
Scalar product OA .OB = 7
Angle ∠ AOB = 23°11'55″ = 0.4049 rad