Line slope calculator 5x-4y=1
Straight line given by points A[1; 1] and B[5; 6]
Calculation:
Slope: m = 1.25Slope-intercept form of line: y = 1.25x-0.25
Canonical form of the line equation: 5x-4y-1 = 0
Parametric form of the line equation:
x = 4t+1
y = 5t+1 ; t ∈ R
Slope angle of line: φ = 51°20'25″ = 0.8961 rad
X intercept: x0 = 0.2
Y intercept: y0 = q = -0.25
Distance line from the origin: d0 = 0.1562
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; 5)
Normal vector: n = (5; -4)
Midpoint of the segment AB: M = [3; 3.5]
Perpendicular Bisector equation: 4x+5y-29.5 = 0
Vector OA = (1; 1) ; |OA| = 1.4142
Vector OB = (5; 6) ; |OB| = 7.8102
Scalar product OA .OB = 11
Angle ∠ AOB = 5°11'40″ = 0.0907 rad