Line slope calculator x-5y=-4
Straight line given by points A[1; 1] and B[6; 2]
Calculation:
Slope: m = 0.2Slope-intercept form of line: y = 0.2x+0.8
Canonical form of the line equation: x-5y+4 = 0
Parametric form of the line equation:
x = 5t+1
y = t+1 ; t ∈ R
Slope angle of line: φ = 11°18'36″ = 0.1974 rad
X intercept: x0 = -4
Y intercept: y0 = q = 0.8
Distance line from the origin: d0 = 0.7845
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; 1)
Normal vector: n = (1; -5)
Midpoint of the segment AB: M = [3.5; 1.5]
Perpendicular Bisector equation: 5x+y-19 = 0
Vector OA = (1; 1) ; |OA| = 1.4142
Vector OB = (6; 2) ; |OB| = 6.3246
Scalar product OA .OB = 8
Angle ∠ AOB = 26°33'54″ = 0.4636 rad