Line slope calculator 4x-5y=-1
Straight line given by points A[1; 1] and B[6; 5]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+0.2
Canonical form of the line equation: 4x-5y+1 = 0
Parametric form of the line equation:
x = 5t+1
y = 4t+1 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -0.25
Y intercept: y0 = q = 0.2
Distance line from the origin: d0 = 0.1562
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [3.5; 3]
Perpendicular Bisector equation: 5x+4y-29.5 = 0
Vector OA = (1; 1) ; |OA| = 1.4142
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 11
Angle ∠ AOB = 5°11'40″ = 0.0907 rad