Line slope calculator 4x-5y=-1


Enter coordinates of two different points:

Straight line given by points A[1; 1] and B[6; 5]

Calculation:

Slope-intercept form of line: y = 0.8x+0.2

Canonical form of the line equation: 4x-5y+1 = 0

Parametric form of the line equation:
x = 5t+1
y = 4t+1      ; t ∈ R

Slope: m = 0.8

Slope angle of line: φ = 38°39'35″ = 0.6747 rad

X intercept: x0 = -0.25

Y intercept: y0 = q = 0.2

Distance line from the origin: d0 = 0.1562

The length of the segment AB: |AB| = 6.4031

Vector: AB = (5; 4)

Normal vector: n = (4; -5)

Midpoint of the segment AB: M = [3.5; 3]

Perpendicular Bisector equation: 5x+4y-29.5 = 0


Vector OA = (1; 1) ;   |OA| = 1.4142
Vector OB = (6; 5) ;   |OB| = 7.8102
Scalar product OA .OB = 11
Angle ∠ AOB = 5°11'40″ = 0.0907 rad