Line slope calculator x+8y=9


Enter coordinates of two different points:

Straight line given by points A[1; 1] and B[9; 0]

Calculation:

Slope-intercept form of line: y = -0.125x+1.125

Canonical form of the line equation: x+8y-9 = 0

Parametric form of the line equation:
x = 8t+1
y = -t+1      ; t ∈ R

Slope: m = -0.125

Slope angle of line: φ = -7°7'30″ = -0.1244 rad

X intercept: x0 = 9

Y intercept: y0 = q = 1.125

Distance line from the origin: d0 = 1.1163

The length of the segment AB: |AB| = 8.0623

Vector: AB = (8; -1)

Normal vector: n = (1; 8)

Midpoint of the segment AB: M = [5; 0.5]

Perpendicular Bisector equation: 8x-y-39.5 = 0


Vector OA = (1; 1) ;   |OA| = 1.4142
Vector OB = (9; 0) ;   |OB| = 9
Scalar product OA .OB = 9
Angle ∠ AOB = 45° = 0.7854 rad