Line slope calculator 5x+9y=95
Straight line given by points A[1; 10] and B[10; 5]
Calculation:
Slope: m = -0.5556Slope-intercept form of line: y = -0.5556x+10.5556
Canonical form of the line equation: 5x+9y-95 = 0
Parametric form of the line equation:
x = 9t+1
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -29°3'17″ = -0.5071 rad
X intercept: x0 = 19
Y intercept: y0 = q = 10.5556
Distance line from the origin: d0 = 9.2272
The length of the segment AB: |AB| = 10.2956
Vector: AB = (9; -5)
Normal vector: n = (5; 9)
Midpoint of the segment AB: M = [5.5; 7.5]
Perpendicular Bisector equation: 9x-5y-12 = 0
Vector OA = (1; 10) ; |OA| = 10.0499
Vector OB = (10; 5) ; |OB| = 11.1803
Scalar product OA .OB = 60
Angle ∠ AOB = 57°43'28″ = 1.0075 rad