Line slope calculator 10x+y=20


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[2; 0]

Calculation:

Slope-intercept form of line: y = -10x+20

Canonical form of the line equation: 10x+y-20 = 0

Parametric form of the line equation:
x = t+1
y = -10t+10      ; t ∈ R

Slope: m = -10

Slope angle of line: φ = -84°17'22″ = -1.4711 rad

X intercept: x0 = 2

Y intercept: y0 = q = 20

Distance line from the origin: d0 = 1.9901

The length of the segment AB: |AB| = 10.0499

Vector: AB = (1; -10)

Normal vector: n = (10; 1)

Midpoint of the segment AB: M = [1.5; 5]

Perpendicular Bisector equation: x-10y+48.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (2; 0) ;   |OB| = 2
Scalar product OA .OB = 2
Angle ∠ AOB = 84°17'22″ = 1.4711 rad