Line slope calculator 6x+y=16


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[2; 4]

Calculation:

Slope-intercept form of line: y = -6x+16

Canonical form of the line equation: 6x+y-16 = 0

Parametric form of the line equation:
x = t+1
y = -6t+10      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 2.6667

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 2.6304

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [1.5; 7]

Perpendicular Bisector equation: x-6y+40.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (2; 4) ;   |OB| = 4.4721
Scalar product OA .OB = 42
Angle ∠ AOB = 20°51'16″ = 0.364 rad