Line slope calculator 5x+y=15


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[2; 5]

Calculation:

Slope-intercept form of line: y = -5x+15

Canonical form of the line equation: 5x+y-15 = 0

Parametric form of the line equation:
x = t+1
y = -5t+10      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 3

Y intercept: y0 = q = 15

Distance line from the origin: d0 = 2.9417

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [1.5; 7.5]

Perpendicular Bisector equation: x-5y+36 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (2; 5) ;   |OB| = 5.3852
Scalar product OA .OB = 52
Angle ∠ AOB = 16°5'27″ = 0.2808 rad