Line slope calculator 2x+y=12


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[2; 8]

Calculation:

Slope-intercept form of line: y = -2x+12

Canonical form of the line equation: 2x+y-12 = 0

Parametric form of the line equation:
x = t+1
y = -2t+10      ; t ∈ R

Slope: m = -2

Slope angle of line: φ = -63°26'6″ = -1.1071 rad

X intercept: x0 = 6

Y intercept: y0 = q = 12

Distance line from the origin: d0 = 5.3666

The length of the segment AB: |AB| = 2.2361

Vector: AB = (1; -2)

Normal vector: n = (2; 1)

Midpoint of the segment AB: M = [1.5; 9]

Perpendicular Bisector equation: x-2y+16.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (2; 8) ;   |OB| = 8.2462
Scalar product OA .OB = 82
Angle ∠ AOB = 8°19'32″ = 0.1453 rad