Line slope calculator 5x+2y=25


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[3; 5]

Calculation:

Slope-intercept form of line: y = -2.5x+12.5

Canonical form of the line equation: 5x+2y-25 = 0

Parametric form of the line equation:
x = 2t+1
y = -5t+10      ; t ∈ R

Slope: m = -2.5

Slope angle of line: φ = -68°11'55″ = -1.1903 rad

X intercept: x0 = 5

Y intercept: y0 = q = 12.5

Distance line from the origin: d0 = 4.6424

The length of the segment AB: |AB| = 5.3852

Vector: AB = (2; -5)

Normal vector: n = (5; 2)

Midpoint of the segment AB: M = [2; 7.5]

Perpendicular Bisector equation: 2x-5y+33.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (3; 5) ;   |OB| = 5.831
Scalar product OA .OB = 53
Angle ∠ AOB = 25°15'11″ = 0.4408 rad