Line slope calculator x+y=11


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[3; 8]

Calculation:

Slope-intercept form of line: y = -x+11

Canonical form of the line equation: x+y-11 = 0

Parametric form of the line equation:
x = t+1
y = -t+10      ; t ∈ R

Slope: m = -1

Slope angle of line: φ = -45° = -0.7854 rad

X intercept: x0 = 11

Y intercept: y0 = q = 11

Distance line from the origin: d0 = 7.7782

The length of the segment AB: |AB| = 2.8284

Vector: AB = (2; -2)

Normal vector: n = (1; 1)

Midpoint of the segment AB: M = [2; 9]

Perpendicular Bisector equation: 2x-2y+14 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (3; 8) ;   |OB| = 8.544
Scalar product OA .OB = 83
Angle ∠ AOB = 14°50'44″ = 0.2591 rad