Line slope calculator 8x+3y=38


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[4; 2]

Calculation:

Slope-intercept form of line: y = -2.6667x+12.6667

Canonical form of the line equation: 8x+3y-38 = 0

Parametric form of the line equation:
x = 3t+1
y = -8t+10      ; t ∈ R

Slope: m = -2.6667

Slope angle of line: φ = -69°26'38″ = -1.212 rad

X intercept: x0 = 4.75

Y intercept: y0 = q = 12.6667

Distance line from the origin: d0 = 4.4476

The length of the segment AB: |AB| = 8.544

Vector: AB = (3; -8)

Normal vector: n = (8; 3)

Midpoint of the segment AB: M = [2.5; 6]

Perpendicular Bisector equation: 3x-8y+40.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (4; 2) ;   |OB| = 4.4721
Scalar product OA .OB = 24
Angle ∠ AOB = 57°43'28″ = 1.0075 rad