Line slope calculator 8x+3y=38
Straight line given by points A[1; 10] and B[4; 2]
Calculation:
Slope: m = -2.6667Slope-intercept form of line: y = -2.6667x+12.6667
Canonical form of the line equation: 8x+3y-38 = 0
Parametric form of the line equation:
x = 3t+1
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -69°26'38″ = -1.212 rad
X intercept: x0 = 4.75
Y intercept: y0 = q = 12.6667
Distance line from the origin: d0 = 4.4476
The length of the segment AB: |AB| = 8.544
Vector: AB = (3; -8)
Normal vector: n = (8; 3)
Midpoint of the segment AB: M = [2.5; 6]
Perpendicular Bisector equation: 3x-8y+40.5 = 0
Vector OA = (1; 10) ; |OA| = 10.0499
Vector OB = (4; 2) ; |OB| = 4.4721
Scalar product OA .OB = 24
Angle ∠ AOB = 57°43'28″ = 1.0075 rad