Line slope calculator 5x+4y=45
Straight line given by points A[1; 10] and B[5; 5]
Calculation:
Slope: m = -1.25Slope-intercept form of line: y = -1.25x+11.25
Canonical form of the line equation: 5x+4y-45 = 0
Parametric form of the line equation:
x = 4t+1
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -51°20'25″ = -0.8961 rad
X intercept: x0 = 9
Y intercept: y0 = q = 11.25
Distance line from the origin: d0 = 7.0278
The length of the segment AB: |AB| = 6.4031
Vector: AB = (4; -5)
Normal vector: n = (5; 4)
Midpoint of the segment AB: M = [3; 7.5]
Perpendicular Bisector equation: 4x-5y+25.5 = 0
Vector OA = (1; 10) ; |OA| = 10.0499
Vector OB = (5; 5) ; |OB| = 7.0711
Scalar product OA .OB = 55
Angle ∠ AOB = 39°17'22″ = 0.6857 rad