Line slope calculator 5x+4y=45


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[5; 5]

Calculation:

Slope-intercept form of line: y = -1.25x+11.25

Canonical form of the line equation: 5x+4y-45 = 0

Parametric form of the line equation:
x = 4t+1
y = -5t+10      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 9

Y intercept: y0 = q = 11.25

Distance line from the origin: d0 = 7.0278

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [3; 7.5]

Perpendicular Bisector equation: 4x-5y+25.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (5; 5) ;   |OB| = 7.0711
Scalar product OA .OB = 55
Angle ∠ AOB = 39°17'22″ = 0.6857 rad