Line slope calculator 9x+5y=59


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -1.8x+11.8

Canonical form of the line equation: 9x+5y-59 = 0

Parametric form of the line equation:
x = 5t+1
y = -9t+10      ; t ∈ R

Slope: m = -1.8

Slope angle of line: φ = -60°56'43″ = -1.0637 rad

X intercept: x0 = 6.5556

Y intercept: y0 = q = 11.8

Distance line from the origin: d0 = 5.7306

The length of the segment AB: |AB| = 10.2956

Vector: AB = (5; -9)

Normal vector: n = (9; 5)

Midpoint of the segment AB: M = [3.5; 5.5]

Perpendicular Bisector equation: 5x-9y+32 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 16
Angle ∠ AOB = 74°49'37″ = 1.306 rad