Line slope calculator 9x+5y=59
Straight line given by points A[1; 10] and B[6; 1]
Calculation:
Slope: m = -1.8Slope-intercept form of line: y = -1.8x+11.8
Canonical form of the line equation: 9x+5y-59 = 0
Parametric form of the line equation:
x = 5t+1
y = -9t+10 ; t ∈ R
Slope angle of line: φ = -60°56'43″ = -1.0637 rad
X intercept: x0 = 6.5556
Y intercept: y0 = q = 11.8
Distance line from the origin: d0 = 5.7306
The length of the segment AB: |AB| = 10.2956
Vector: AB = (5; -9)
Normal vector: n = (9; 5)
Midpoint of the segment AB: M = [3.5; 5.5]
Perpendicular Bisector equation: 5x-9y+32 = 0
Vector OA = (1; 10) ; |OA| = 10.0499
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 16
Angle ∠ AOB = 74°49'37″ = 1.306 rad