Line slope calculator 8x+5y=58


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[6; 2]

Calculation:

Slope-intercept form of line: y = -1.6x+11.6

Canonical form of the line equation: 8x+5y-58 = 0

Parametric form of the line equation:
x = 5t+1
y = -8t+10      ; t ∈ R

Slope: m = -1.6

Slope angle of line: φ = -57°59'41″ = -1.0122 rad

X intercept: x0 = 7.25

Y intercept: y0 = q = 11.6

Distance line from the origin: d0 = 6.148

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; -8)

Normal vector: n = (8; 5)

Midpoint of the segment AB: M = [3.5; 6]

Perpendicular Bisector equation: 5x-8y+30.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (6; 2) ;   |OB| = 6.3246
Scalar product OA .OB = 26
Angle ∠ AOB = 65°51'16″ = 1.1494 rad