Line slope calculator 2x+5y=52
Straight line given by points A[1; 10] and B[6; 8]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+10.4
Canonical form of the line equation: 2x+5y-52 = 0
Parametric form of the line equation:
x = 5t+1
y = -2t+10 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 26
Y intercept: y0 = q = 10.4
Distance line from the origin: d0 = 9.6562
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [3.5; 9]
Perpendicular Bisector equation: 5x-2y+0.5 = 0
Vector OA = (1; 10) ; |OA| = 10.0499
Vector OB = (6; 8) ; |OB| = 10
Scalar product OA .OB = 86
Angle ∠ AOB = 31°9'33″ = 0.5438 rad