Line slope calculator 10x+7y=80


Enter coordinates of two different points:

Straight line given by points A[1; 10] and B[8; 0]

Calculation:

Slope-intercept form of line: y = -1.4286x+11.4286

Canonical form of the line equation: 10x+7y-80 = 0

Parametric form of the line equation:
x = 7t+1
y = -10t+10      ; t ∈ R

Slope: m = -1.4286

Slope angle of line: φ = -55°29″ = -0.9601 rad

X intercept: x0 = 8

Y intercept: y0 = q = 11.4286

Distance line from the origin: d0 = 6.5539

The length of the segment AB: |AB| = 12.2066

Vector: AB = (7; -10)

Normal vector: n = (10; 7)

Midpoint of the segment AB: M = [4.5; 5]

Perpendicular Bisector equation: 7x-10y+18.5 = 0


Vector OA = (1; 10) ;   |OA| = 10.0499
Vector OB = (8; 0) ;   |OB| = 8
Scalar product OA .OB = 8
Angle ∠ AOB = 84°17'22″ = 1.4711 rad