Line slope calculator 2x-9y=-16
Straight line given by points A[1; 2] and B[10; 4]
Calculation:
Slope: m = 0.2222Slope-intercept form of line: y = 0.2222x+1.7778
Canonical form of the line equation: 2x-9y+16 = 0
Parametric form of the line equation:
x = 9t+1
y = 2t+2 ; t ∈ R
Slope angle of line: φ = 12°31'44″ = 0.2187 rad
X intercept: x0 = -8
Y intercept: y0 = q = 1.7778
Distance line from the origin: d0 = 1.7354
The length of the segment AB: |AB| = 9.2195
Vector: AB = (9; 2)
Normal vector: n = (2; -9)
Midpoint of the segment AB: M = [5.5; 3]
Perpendicular Bisector equation: 9x+2y-55.5 = 0
Vector OA = (1; 2) ; |OA| = 2.2361
Vector OB = (10; 4) ; |OB| = 10.7703
Scalar product OA .OB = 18
Angle ∠ AOB = 41°38'1″ = 0.7266 rad