Line slope calculator x+2y=5
Straight line given by points A[1; 2] and B[3; 1]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+2.5
Canonical form of the line equation: x+2y-5 = 0
Parametric form of the line equation:
x = 2t+1
y = -t+2 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 5
Y intercept: y0 = q = 2.5
Distance line from the origin: d0 = 2.2361
The length of the segment AB: |AB| = 2.2361
Vector: AB = (2; -1)
Normal vector: n = (1; 2)
Midpoint of the segment AB: M = [2; 1.5]
Perpendicular Bisector equation: 2x-y-2.5 = 0
Vector OA = (1; 2) ; |OA| = 2.2361
Vector OB = (3; 1) ; |OB| = 3.1623
Scalar product OA .OB = 5
Angle ∠ AOB = 45° = 0.7854 rad