Line slope calculator x+3y=7
Straight line given by points A[1; 2] and B[4; 1]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+2.3333
Canonical form of the line equation: x+3y-7 = 0
Parametric form of the line equation:
x = 3t+1
y = -t+2 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 7
Y intercept: y0 = q = 2.3333
Distance line from the origin: d0 = 2.2136
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [2.5; 1.5]
Perpendicular Bisector equation: 3x-y-6 = 0
Vector OA = (1; 2) ; |OA| = 2.2361
Vector OB = (4; 1) ; |OB| = 4.1231
Scalar product OA .OB = 6
Angle ∠ AOB = 49°23'55″ = 0.8622 rad