Line slope calculator x-3y=-5


Enter coordinates of two different points:

Straight line given by points A[1; 2] and B[4; 3]

Calculation:

Slope-intercept form of line: y = 0.3333x+1.6667

Canonical form of the line equation: x-3y+5 = 0

Parametric form of the line equation:
x = 3t+1
y = t+2      ; t ∈ R

Slope: m = 0.3333

Slope angle of line: φ = 18°26'6″ = 0.3218 rad

X intercept: x0 = -5

Y intercept: y0 = q = 1.6667

Distance line from the origin: d0 = 1.5811

The length of the segment AB: |AB| = 3.1623

Vector: AB = (3; 1)

Normal vector: n = (1; -3)

Midpoint of the segment AB: M = [2.5; 2.5]

Perpendicular Bisector equation: 3x+y-10 = 0


Vector OA = (1; 2) ;   |OA| = 2.2361
Vector OB = (4; 3) ;   |OB| = 5
Scalar product OA .OB = 10
Angle ∠ AOB = 26°33'54″ = 0.4636 rad