Line slope calculator x+5y=11
Straight line given by points A[1; 2] and B[6; 1]
Calculation:
Slope: m = -0.2Slope-intercept form of line: y = -0.2x+2.2
Canonical form of the line equation: x+5y-11 = 0
Parametric form of the line equation:
x = 5t+1
y = -t+2 ; t ∈ R
Slope angle of line: φ = -11°18'36″ = -0.1974 rad
X intercept: x0 = 11
Y intercept: y0 = q = 2.2
Distance line from the origin: d0 = 2.1573
The length of the segment AB: |AB| = 5.099
Vector: AB = (5; -1)
Normal vector: n = (1; 5)
Midpoint of the segment AB: M = [3.5; 1.5]
Perpendicular Bisector equation: 5x-y-16 = 0
Vector OA = (1; 2) ; |OA| = 2.2361
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 8
Angle ∠ AOB = 53°58'21″ = 0.942 rad