Line slope calculator 8x-5y=-2
Straight line given by points A[1; 2] and B[6; 10]
Calculation:
Slope: m = 1.6Slope-intercept form of line: y = 1.6x+0.4
Canonical form of the line equation: 8x-5y+2 = 0
Parametric form of the line equation:
x = 5t+1
y = 8t+2 ; t ∈ R
Slope angle of line: φ = 57°59'41″ = 1.0122 rad
X intercept: x0 = -0.25
Y intercept: y0 = q = 0.4
Distance line from the origin: d0 = 0.212
The length of the segment AB: |AB| = 9.434
Vector: AB = (5; 8)
Normal vector: n = (8; -5)
Midpoint of the segment AB: M = [3.5; 6]
Perpendicular Bisector equation: 5x+8y-65.5 = 0
Vector OA = (1; 2) ; |OA| = 2.2361
Vector OB = (6; 10) ; |OB| = 11.6619
Scalar product OA .OB = 26
Angle ∠ AOB = 4°23'55″ = 0.0768 rad