Line slope calculator x-5y=-9


Enter coordinates of two different points:

Straight line given by points A[1; 2] and B[6; 3]

Calculation:

Slope-intercept form of line: y = 0.2x+1.8

Canonical form of the line equation: x-5y+9 = 0

Parametric form of the line equation:
x = 5t+1
y = t+2      ; t ∈ R

Slope: m = 0.2

Slope angle of line: φ = 11°18'36″ = 0.1974 rad

X intercept: x0 = -9

Y intercept: y0 = q = 1.8

Distance line from the origin: d0 = 1.765

The length of the segment AB: |AB| = 5.099

Vector: AB = (5; 1)

Normal vector: n = (1; -5)

Midpoint of the segment AB: M = [3.5; 2.5]

Perpendicular Bisector equation: 5x+y-20 = 0


Vector OA = (1; 2) ;   |OA| = 2.2361
Vector OB = (6; 3) ;   |OB| = 6.7082
Scalar product OA .OB = 12
Angle ∠ AOB = 36°52'12″ = 0.6435 rad