Line slope calculator 4x-5y=-6
Straight line given by points A[1; 2] and B[6; 6]
Calculation:
Slope: m = 0.8Slope-intercept form of line: y = 0.8x+1.2
Canonical form of the line equation: 4x-5y+6 = 0
Parametric form of the line equation:
x = 5t+1
y = 4t+2 ; t ∈ R
Slope angle of line: φ = 38°39'35″ = 0.6747 rad
X intercept: x0 = -1.5
Y intercept: y0 = q = 1.2
Distance line from the origin: d0 = 0.937
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; 4)
Normal vector: n = (4; -5)
Midpoint of the segment AB: M = [3.5; 4]
Perpendicular Bisector equation: 5x+4y-33.5 = 0
Vector OA = (1; 2) ; |OA| = 2.2361
Vector OB = (6; 6) ; |OB| = 8.4853
Scalar product OA .OB = 18
Angle ∠ AOB = 18°26'6″ = 0.3218 rad