Line slope calculator x+6y=13


Enter coordinates of two different points:

Straight line given by points A[1; 2] and B[7; 1]

Calculation:

Slope-intercept form of line: y = -0.1667x+2.1667

Canonical form of the line equation: x+6y-13 = 0

Parametric form of the line equation:
x = 6t+1
y = -t+2      ; t ∈ R

Slope: m = -0.1667

Slope angle of line: φ = -9°27'44″ = -0.1651 rad

X intercept: x0 = 13

Y intercept: y0 = q = 2.1667

Distance line from the origin: d0 = 2.1372

The length of the segment AB: |AB| = 6.0828

Vector: AB = (6; -1)

Normal vector: n = (1; 6)

Midpoint of the segment AB: M = [4; 1.5]

Perpendicular Bisector equation: 6x-y-22.5 = 0


Vector OA = (1; 2) ;   |OA| = 2.2361
Vector OB = (7; 1) ;   |OB| = 7.0711
Scalar product OA .OB = 9
Angle ∠ AOB = 55°18'17″ = 0.9653 rad