Line slope calculator x+7y=15


Enter coordinates of two different points:

Straight line given by points A[1; 2] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -0.1429x+2.1429

Canonical form of the line equation: x+7y-15 = 0

Parametric form of the line equation:
x = 7t+1
y = -t+2      ; t ∈ R

Slope: m = -0.1429

Slope angle of line: φ = -8°7'48″ = -0.1419 rad

X intercept: x0 = 15

Y intercept: y0 = q = 2.1429

Distance line from the origin: d0 = 2.1213

The length of the segment AB: |AB| = 7.0711

Vector: AB = (7; -1)

Normal vector: n = (1; 7)

Midpoint of the segment AB: M = [4.5; 1.5]

Perpendicular Bisector equation: 7x-y-30 = 0


Vector OA = (1; 2) ;   |OA| = 2.2361
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 10
Angle ∠ AOB = 56°18'36″ = 0.9828 rad