Line slope calculator 2x+3y=11


Enter coordinates of two different points:

Straight line given by points A[1; 3] and B[4; 1]

Calculation:

Slope-intercept form of line: y = -0.6667x+3.6667

Canonical form of the line equation: 2x+3y-11 = 0

Parametric form of the line equation:
x = 3t+1
y = -2t+3      ; t ∈ R

Slope: m = -0.6667

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 5.5

Y intercept: y0 = q = 3.6667

Distance line from the origin: d0 = 3.0509

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [2.5; 2]

Perpendicular Bisector equation: 3x-2y-3.5 = 0


Vector OA = (1; 3) ;   |OA| = 3.1623
Vector OB = (4; 1) ;   |OB| = 4.1231
Scalar product OA .OB = 7
Angle ∠ AOB = 57°31'44″ = 1.0041 rad