Line slope calculator 3x+4y=15


Enter coordinates of two different points:

Straight line given by points A[1; 3] and B[5; 0]

Calculation:

Slope-intercept form of line: y = -0.75x+3.75

Canonical form of the line equation: 3x+4y-15 = 0

Parametric form of the line equation:
x = 4t+1
y = -3t+3      ; t ∈ R

Slope: m = -0.75

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 5

Y intercept: y0 = q = 3.75

Distance line from the origin: d0 = 3

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [3; 1.5]

Perpendicular Bisector equation: 4x-3y-7.5 = 0


Vector OA = (1; 3) ;   |OA| = 3.1623
Vector OB = (5; 0) ;   |OB| = 5
Scalar product OA .OB = 5
Angle ∠ AOB = 71°33'54″ = 1.249 rad