Line slope calculator x+4y=13


Enter coordinates of two different points:

Straight line given by points A[1; 3] and B[5; 2]

Calculation:

Slope-intercept form of line: y = -0.25x+3.25

Canonical form of the line equation: x+4y-13 = 0

Parametric form of the line equation:
x = 4t+1
y = -t+3      ; t ∈ R

Slope: m = -0.25

Slope angle of line: φ = -14°2'10″ = -0.245 rad

X intercept: x0 = 13

Y intercept: y0 = q = 3.25

Distance line from the origin: d0 = 3.153

The length of the segment AB: |AB| = 4.1231

Vector: AB = (4; -1)

Normal vector: n = (1; 4)

Midpoint of the segment AB: M = [3; 2.5]

Perpendicular Bisector equation: 4x-y-9.5 = 0


Vector OA = (1; 3) ;   |OA| = 3.1623
Vector OB = (5; 2) ;   |OB| = 5.3852
Scalar product OA .OB = 11
Angle ∠ AOB = 49°45'49″ = 0.8685 rad