Line slope calculator x-4y=-11
Straight line given by points A[1; 3] and B[5; 4]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x+2.75
Canonical form of the line equation: x-4y+11 = 0
Parametric form of the line equation:
x = 4t+1
y = t+3 ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = -11
Y intercept: y0 = q = 2.75
Distance line from the origin: d0 = 2.6679
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [3; 3.5]
Perpendicular Bisector equation: 4x+y-15.5 = 0
Vector OA = (1; 3) ; |OA| = 3.1623
Vector OB = (5; 4) ; |OB| = 6.4031
Scalar product OA .OB = 17
Angle ∠ AOB = 32°54'19″ = 0.5743 rad