Line slope calculator 3x+5y=18
Straight line given by points A[1; 3] and B[6; 0]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+3.6
Canonical form of the line equation: 3x+5y-18 = 0
Parametric form of the line equation:
x = 5t+1
y = -3t+3 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 6
Y intercept: y0 = q = 3.6
Distance line from the origin: d0 = 3.087
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [3.5; 1.5]
Perpendicular Bisector equation: 5x-3y-13 = 0
Vector OA = (1; 3) ; |OA| = 3.1623
Vector OB = (6; 0) ; |OB| = 6
Scalar product OA .OB = 6
Angle ∠ AOB = 71°33'54″ = 1.249 rad