Line slope calculator 7x-5y=-8
Straight line given by points A[1; 3] and B[6; 10]
Calculation:
Slope: m = 1.4Slope-intercept form of line: y = 1.4x+1.6
Canonical form of the line equation: 7x-5y+8 = 0
Parametric form of the line equation:
x = 5t+1
y = 7t+3 ; t ∈ R
Slope angle of line: φ = 54°27'44″ = 0.9505 rad
X intercept: x0 = -1.1429
Y intercept: y0 = q = 1.6
Distance line from the origin: d0 = 0.93
The length of the segment AB: |AB| = 8.6023
Vector: AB = (5; 7)
Normal vector: n = (7; -5)
Midpoint of the segment AB: M = [3.5; 6.5]
Perpendicular Bisector equation: 5x+7y-63 = 0
Vector OA = (1; 3) ; |OA| = 3.1623
Vector OB = (6; 10) ; |OB| = 11.6619
Scalar product OA .OB = 36
Angle ∠ AOB = 12°31'44″ = 0.2187 rad